Kogorous Riddle Thread and eworms Deduction Thread

[Rein]

Only using letters found in 'Flute' and 'Ocean': Disproved?

Spoiler:

If you wite oceanflut (ignoring the second 'e') and simply number the letters in the order they appear, which comes to: 723164598. Then keeping to the number pattern, if you rearrange the letters according to 749....etc. you end upend with: ofuaecntl - which doesn't make sense.

[miyano_shiho]

Yeah, that's what I've tried too.

...Any more hints, Kamite?

[Kamite]

For one thing "Ocean" and "Flute" are not related with the word. The word is a compound and it would not work if you try to split it. Last thing the number position and meaning are important.

[Raifuujin]

I came up with an idea while I was trying to go to sleep last night, but it might be time consuming...

Spoiler:

Well, we can assume that 1 will be 'a' for now. If it is 'a', the lowest letter 2 can be is 'b'. Continuing that, 'i' is the lowest letter 9 can be. However, just using the first nine letters wouldn't make sense, so you change which letters you use for the numbers by one letter, which pushes the rest of the letters up by one.

7  4  9  1  3  2  6  8  5       7  4  9  1  3  2  6  8  5
g  d   i  a   c  b  f   h  e  -->g  d  i  a  c  b  f  h  e
                                         h  e  j     d  c  g  i   f

And when you get to a place that looks like it might work, just don't change that letter.

7  4  9  1  3  2  6  8  5       7  4  9  1  3  2  6  8  5
g  d   i  a  c   b  f   h  e  -->g  d   i  a  c   b  f   h  e
h  e   j  a  d  c  g   i   f        h  e  j   a  d  c  g   i   f
i   f  k a  e  d  h   j  g        i   f   k  a  e  d  h  j   g
j   g   l  a  f   e  i   k  h        j  g   l   a   f  e  i   k  h
                                        k  h  m  a  g  e  j  l  i

One can keep going until the word starts making sense, and if 'a' is not number 1, then it can be started over again with 'b' as 1 instead. I'm not entirely sure this is how it's supposed to be solved, and it probably has problems in how it is done, but I think it could work. One just needs a lot of time and patience (and I don't quite have the 'time' part right now, but will be working on this when I can.)

[Kamite]

Good work. You are right on track.

[sstimson]

Slightly Off Topic

As this riddle is killing the thread, how about an easier one, while Kamite's one is worked on.

Palindrome

Something you hope to never see at the circus

-------- ---- ----.





If no guess by 11-25-2012, will post the answer

[Raifuujin]

Ok, I'll try the palindrome.

Spoiler:

Acrobats stab orca?

[sstimson]

Yep.

[Jecka]

Ok, I'll try the palindrome.

Spoiler:

Acrobats stab orca?

That poor orca T_T

[Jefufuh]

Ok, I'll try the palindrome.

Spoiler:

Acrobats stab orca?

That poor orca T_T

Where are the animal rights activists when we need them?

[Kamite]

Forgot about my own riddle.
Answer

Spoiler:

P  i  t  c  h f  o r  k
7 4  9 1 3 2 6 8  5

[sstimson]

Do not fear to answer this palindrome

-----------

Answer on December 7

need help? Try googling the words fear and palindrome.

or click this link

[miyano_shiho]

I actually thought of that but I said to myself, "It's probably wrong. It doesn't even sound like a word." XD



More riddles, anyone? I'm missing this thread.

[no one]

I don't know if you already know this but here goes...

You have 20 cards, 6 with faces up and 14 with faces down. You are in a dark room and you can't see them. How will you divide the cards into two groups so that the number of cards with faces up in each group are equal? Flipping the cards is allowed.

has anyone solved this riddle?

[Kogorou]

I don't know if you already know this but here goes...

You have 20 cards, 6 with faces up and 14 with faces down. You are in a dark room and you can't see them. How will you divide the cards into two groups so that the number of cards with faces up in each group are equal? Flipping the cards is allowed.

has anyone solved this riddle?

That's a gambling question